Let's Play Chess
Reshevsky Keeps Slim Lead In Buenos Aires Tournament
By William Oaker
United States Grandmaster Sammy Reshevsky continues to cling tenaciously to his lead in the Buenos Aires International Tournament with only two rounds remaining to be played.
During the last four rounds Victor Korchnoi, U.S.S.R. champion, has put on a tremendous drive, only to have the stubborn American match him point for point, and thus cling to his slim half-point lead.
It now looks as though only Reshevsky and Korchnoi have a chance to win the tourney, although, Laszlo Szabo, of Hungary, has a bare mathematical chance, as does Larry Evans, another American Grandmaster.
Standings and scores after 17 rounds are as follows:
Reshevsky, United States, 12-5;
Korchnoi, Soviet Union, 11½-5½;
Szabo, Hungary, 10½-6½;
Olafsson, Iceland, 10-7;
Evans, United States, and Taimanov, Soviet Union, 9½-6½;
Guimard, Argentina, 9½-7½;
Unzicker, Germany, 9-7;
Rossetto, Argentina, 9-8;
Gligoric, Yugoslavia, and Uhlmann, Germany, 8½-8½;
Pachman, Czechoslovakia, 8-9;
Wexler, Argentina, 7½-8½
Fischer and Benko, both of United States, 7½-9½;
Ivkov, Yugoslavia, 7-9;
Eliskases, Argentina, 7-10;
Foguelman, Argentina, 5½-11½;
Wade, New Zealand, 5-13;
and Bazan, Argentina, 4½-11½.
Both Taimanov and Evans have adjourned games. Taimanov must complete his game against Unzicker and the position is thought to be drawish. Evans is a pawn ahead against Wexler and is thought to have good chances of winning which would tie him with Szabo.
How Good Are You?
FEN k4r2/1R4pb/1pQp1n1p/3P4/5p1P/3P2P1/r1q1R2K/8 w - - 0 1
White to Play and Win
There are interesting psychological factors in chess and this position is a good example. Let us put it this way: we expect you will be surprised at how simple the solution is once you see it. But, for some strange reason, a number of good players have looked at it long and hard without being able to crack it. On the other hand, I have seen somewhat lesser players grasp the solution almost instantly. Remember, it really is quite simple.
Solution:
1. Rxb6+ Qxc6
2. Rxa2+ Qa4
3. Rxa4#